Leopard Math
Do two 800 MHz PowerPC processors count collectively against a single 867 MHz PowerPC system requirement? In Mac OS X 10.5 Leopard, 800*2 != 1600.
In Mac OS X 10.5 Leopard, 800*2 != 1600. I was thinking that this was probably the case, so I opted for the single use license for Leopard instead of the family pack to upgrade only one of my Macs for now. I have a dual 800 MHz Power Mac G4 and a first generation MacBook.
Out of the tens of thousands of Leopard reviews and first impressions I read this week, exactly zero addressed my top two questions:
- Does the Leopard install disk work on both PowerPC and Intel processors?
- Do two 800 MHz PowerPC processors count collectively against the minimum 867 MHz PowerPC system requirement?
The answer to number one is yes. The answer to number two is no.
This bums me out a little. My Dual 800 MHz Power Mac has treaded me well (and is as I type this). It is, however, quite long in the tooth, and really does show it's age when compared to my humbly powered low end MacBook. Because of this, it has been relegated to family duty, i.e. banking, music library, internet, etc..
The ability to only read 120GB partitions, the lack of an iSight camera, excess fan hum and access to ports on the back are really becoming cumbersome. As my MacBook hums along with its Leopard upgrade in the corner over there, I foresee my Quicksilver's inability to run Leopard as being the final straw. Especially when I consider the piece of mind TimeMachine could offer in regards to my family photos.
It's iMac time, I think.